(4x)^2=16x^2

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Solution for (4x)^2=16x^2 equation: 



(4x)^2=16x^2

We move all terms to the left:

(4x)^2-(16x^2)=0

We add all the numbers together, and all the variables

-12x^2=0

a = -12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-12)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-24}=0$

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